Answer:
Area of parallelogram ABC \[=\text{base}\times \text{height}\] \[\text{= AD }\!\!\times\!\!\text{ BM}\] \[\Rightarrow \] \[\text{1470 = 49 }\!\!\times\!\!\text{ BM}\] \[\Rightarrow \] \[\text{BM = }\frac{\text{1470}}{\text{49}}\text{ cm}\] \[\Rightarrow \] \[\text{BM = 30 cm}\] Hence, the length of BM is 30 cm. Again, area of parallelogram ABCD \[=\text{base}\times \text{height}\] \[\text{= AB }\!\!\times\!\!\text{ DL}\] \[\Rightarrow \] \[\text{1470 = 35 }\!\!\times\!\!\text{ DL}\] \[\Rightarrow \] \[\text{DL = }\frac{\text{1470}}{\text{35}}\text{ cm}\] \[\Rightarrow \] \[\text{DL = 42 cm}\] Hence, the length of DL is 42 cm.
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