Answer:
Area of the roads = Area of the rectangle PQRS + Area of the rectangle EFGH ? Area of the square KLMN \[=(\text{3}00\times \text{1}0+\text{7}00\times \text{1}0-\text{1}0\times \text{1}0)\text{ }{{\text{m}}^{\text{2}}}\] \[=(\text{3}000+\text{7}000-\text{1}00)\text{ }{{\text{m}}^{\text{2}}}=\text{999}0\text{ }{{\text{m}}^{\text{2}}}\] or \[=\frac{9900}{10000}=0.99\,ha\]. Area of the rectangle \[\text{ABCD }=l\text{ }\times \text{ }b\text{ = 700 m }\!\!\times\!\!\text{ 300 m = 210000 }{{\text{m}}^{\text{2}}}\] \[\therefore \] Area of the park excluding cross roads = Area of the rectangle ABCD ? Area of the roads \[\text{= 210000 }{{\text{m}}^{\text{2}}}\text{- 9990 }{{\text{m}}^{\text{2}}}\text{= 200010 }{{\text{m}}^{\text{2}}}\] \[\text{=}\frac{200010}{10000}\text{ hectar}=20.00\text{1 hectare}\text{.}\]
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