Answer:
Area of the rectangle \[\text{PQRS}=l\times b\] \[=\text{5}.\text{5 m}\times \text{4 m}=\text{22 }{{\text{m}}^{\text{2}~}}\] Area of the rectangle ABCD \[=l\times b\] \[\text{= (5}\text{.5 + 2}\text{.25 + 2}\text{.25) m }\!\!\times\!\!\text{ (4 + 2}\text{.25 + 2}\text{.25) m}\] \[\text{= 10 }\!\!\times\!\!\text{ 8}\text{.50 }{{\text{m}}^{\text{2}}}\text{ = 85 }{{\text{m}}^{\text{2}}}\] (i) Area of the verandah = Area of the rectangle ABCD ? Area of the rectangle PQRS \[\text{= 85 }{{\text{m}}^{\text{2}}}\text{-22 }{{\text{m}}^{\text{2}}}\text{= 63 }{{\text{m}}^{\text{2}}}\] (ii) Cost of cementing the floor of the verandah at the rate of ` 200 per \[{{\text{m}}^{\text{2}}}\] = ` \[63\times 200=\] ` 12,600
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