Answer:
Diameter of the flower bed\[=\text{66 m}\] \[\Rightarrow \] Radius of the flower bed (r) \[\text{= }\frac{\text{66}}{\text{2}}\text{m = 33 m}\] \[\therefore \] Area of the flower bed \[=\pi {{r}^{2}}\] \[\text{= 3}\text{.14 }\!\!\times\!\!\text{ (33}{{\text{)}}^{\text{2}}}\text{ }{{\text{m}}^{\text{2}}}\] \[\text{= 3}\text{.14 }\!\!\times\!\!\text{ 1089 }{{\text{m}}^{\text{2}}}\text{ = 3419}\text{.46 }{{\text{m}}^{\text{2}}}\] Radius of the flower bed with path (R) \[=\text{33 m}+\text{4 m}=\text{37 m}\] \[\therefore \] Area of the flower bed with path \[=\pi {{R}^{2}}\] \[=\text{3}.\text{14}\times {{(\text{37})}^{\text{2}}}{{\text{m}}^{\text{2}}}=\text{3}.\text{14}\times \text{1369 }{{\text{m}}^{\text{2}}}\] \[=\text{4298}.\text{66 }{{\text{m}}^{\text{2}}}\] \[\therefore \] Area of the path = Area of the flower bed with path - Area of the flower bed \[=\text{4298}.\text{66 }{{\text{m}}^{\text{2}}}-\text{3419}.\text{46 }{{\text{m}}^{\text{2}}}\] \[\text{= 879}\text{.20 }{{\text{m}}^{\text{2}}}\]
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