8th Class Mathematics Mensuration

  • question_answer 4)
                    A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area \[1080\,\,{{m}^{2}}\]? (If required you can split the tiles in whatever way you want to fill up the corners).

    Answer:

                    Area of a flooring tile \[=24\times 10\,c{{m}^{2}}\] \[=240\,c{{m}^{2}}\] Area of the floor \[=1080\,{{m}^{2}}\] \[=1080\times 100\times 100\,c{{m}^{2}}\] \[\therefore \] Number of tiles required \[=\frac{\text{Area}\,\text{of}\,\text{the}\,\text{floor}}{\text{Area}\,\text{of}\,\text{a}\,\text{flooring}\,\text{file}}\] \[=\frac{1080\times 100\times 100}{240}\] = 45000.


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