Answer:
\[r=\,7\,m\] \[h=\,3\,m\] \[\therefore \] Total surface area \[=2\pi r(r+h)\] \[=2\times \frac{22}{7}\,\times 7\times (7+3)\] \[=440\,{{m}^{2}}\] Hence, \[440\,{{m}^{2}}\] of metal sheet is required.
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