question_answer 1)

                A suitcase with measures \[80\text{ }cm\times 48\text{ }cm\times 24\text{ }cm\] is to be covered with a tarpaulin cloth. How many metres of trapaulin of width 96 cm is required to cover 100 such suitcases?

Answer:

                Total surface area of the suitcase \[=2(80\times 48+48\times 24+24\times 80)\,c{{m}^{2}}\] \[=2(3840+1152+1920)\,c{{m}^{2}}\] \[=2(6912)\,\,c{{m}^{2}}\] \[=13824\,\,c{{m}^{2}}\] \[\therefore \] Length of trapaulin required to cover 1 suitcase                            Total surface area of the suitcase width of trapaulin \[=\frac{13824}{96}\] = 144 cm \[\therefore \] Length of trapaulin required to cover 100 such suitcases \[=144\times 100\,cm\] = 14400 cm = 144 m Hence, 144 m of trapaulin is required.