question_answer 1)

                Diagram of the adjacent picture frame has outer dimensions \[=24cm\times 28\,cm\] and inner dimensions \[=16\,\,cm\times 20\,\,cm\]. Find the area of each section of the frame, if the width of each section is same.

Answer:

                Area of the right section of the frame \[=\frac{(28+20)\times \,\frac{1}{2}\,(24-16)}{2}c{{m}^{2}}\] \[=\frac{48\times 4}{2}c{{m}^{2}}\] \[=96\,c{{m}^{2}}\] Similarly, area of the left section of the frame \[=96\,c{{m}^{2}}\] Area of the upper section of the frame \[=\frac{(24\times 16)\,\frac{1}{2}\,(28-20)}{2}c{{m}^{2}}\] \[=\frac{40\times 4}{2}\,c{{m}^{2}}\] \[=80c{{m}^{2}}\] Similarly, area of the lower section of the frame \[=80c{{m}^{2}}\] .