8th Class Mathematics Mensuration

  • question_answer 1)
                    Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of \[Rs\,55\,per\,{{m}^{2}}\].

    Answer:

                    Area of the square plot \[=25\times 25\,{{m}^{2}}=625\,{{m}^{2}}\] Area of the house \[=20\times 15\,{{m}^{2}}=300\,{{m}^{2}}\] \[\therefore \] Area of the garden = Area of the square plot ? Area of the house \[=625\,{{m}^{2}}-300\,{{m}^{2}}\] \[=325\,{{m}^{2}}\] \[\because \]     The cost of developing the garden per square metre = Rs 55. \[\therefore \] Total cost of developing the garden \[=Rs\,\,325\times 55\] = Rs 17,875.


You need to login to perform this action.
You will be redirected in 3 sec spinner