6th Class Mathematics Mensuration

  • question_answer 1)
    Find the areas of the following figures by counting square.

    Answer:

    (a) Given figure is covered by 9 full squares. \[\therefore \] Area \[=9\times 1\]sq unit = 9 sq units (b) Given figure is covered by 5 full squares. \[\therefore \] Area \[=5\times 1\]sq unit= 5 sq units (c) Given figure is covered by 2 full squares and 4 half squares. \[\therefore \] Area sq units \[=(2+2)\] sq units = 4 sq units (d) Given figure is covered by 8 full squares. \[\therefore \] Area \[=\text{ }8\times 1=8\] sq units (e) Given figure is covered by 10 full squares. \[\therefore \] Area \[=10\times 1\]sq unit = 10 sq units (f) Given figure is covered by 2 full squares and 4 half squares. \[\therefore \] Area \[=\left( 2\times 1+4\times \frac{1}{2} \right)\] sq units \[=(2+2)\]sq units = 4 sq units (g) Given figure is covered by 4 full squares and 4 half squares. \[\therefore \] Area \[=\left( 4\times 1+4\times \frac{1}{2} \right)\] sq units \[=(4+2)sq\] units = 6 sq units (h) Given figure is covered by 5 full squares. \[\therefore \] Area \[=(5\times 1)\,\text{sq}\] units = 5 sq units Given figure is covered by 9 full squares. \[\therefore \] Area \[=(9\times 1)\,\text{sq}\] units = 9 sq units (j) Given figure is covered by 2 full squares and 4 half squares. \[\therefore \] Area \[=\left( 2\times 1+4\times \frac{1}{2} \right)\]sq units = (2 + 2) sq units = 4 sq units (k) Given figure is covered by 4 full squares and 2 half squares. \[\therefore \] Area \[=\left( 4\times 1+2\times \frac{1}{2} \right)\] sq units = (4 + 1) sq units = 5 sq units (l) Given figure is covered by 3 full squares, 4 half squares, 3 more than half squares and 1 less than half square. \[\therefore \]\[=\left( 3\times 1+4\times \frac{1}{2}+3\times 1+1\times 0 \right)\] sq units = (3 + 2 + 3 + 0) sq unit = 8 sq units (m) Given figure is covered by 7 full squares, 8 half squares, 3 more than half squares and 3 less than half squares \[\therefore \] Area \[=\left( 7\times 1+8\times \frac{1}{2}+3\times 1+3\times 0 \right)\] \[=(3+2+3+0)\]sq units = 8 sq units (n) Given figure is covered by 9 full squares, 6 half squares, 6 more than half squares and 4 less than half squares. \[\therefore \] Area \[=\left( 9\times 1+6\times \frac{1}{2}+6\times 1+4\times 0 \right)\]sq units = (9 + 3 + 6 + 0) sq units = 18 sq units


You need to login to perform this action.
You will be redirected in 3 sec spinner