Answer:
Let the smaller number be \[x\]. Then, the larger number \[=x+15\] \[\because \] Sum of two numbers is 95 \[\therefore \] \[x+(x+15)=95\] \[\Rightarrow \] \[2x+15=95\] \[\Rightarrow \] \[2x=95-15\] | Transposing 15 to RHS \[\Rightarrow \] \[2x=80\] \[\Rightarrow \] \[x=\frac{80}{2}=40\] | Dividing both sides by 2 \[\Rightarrow \] \[x+15=40+15=55\] Hence, the desired numbers are 40 and 55. Check: 55 = 40 + 15 | as desired \[40+55=95\].
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