Answer:
Let the number be \[x\]. According to the question, \[\frac{5}{2}x+\frac{2}{3}=-\frac{7}{12}\] \[\Rightarrow \] \[\frac{5}{2}x=-\frac{2}{3}-\frac{7}{12}\] | Transposing \[\frac{2}{3}\] to RHS \[\Rightarrow \] \[\frac{5}{2}x=\frac{-8-7}{12}\] \[\Rightarrow \] \[\frac{5}{2}x=-\frac{15}{12}\] \[\Rightarrow \] \[x=-\frac{15}{12}\times \frac{2}{5}\] | Multiplying both sides by \[\frac{2}{5}\] \[\Rightarrow \] \[x=-\frac{1}{2}\] Hence, the desired rational number is \[-\frac{1}{2}\]. Check: \[\left( -\frac{1}{2} \right)\times \frac{5}{2}+\frac{2}{3}=-\frac{5}{4}+\frac{2}{3}\] \[=\frac{-15+8}{12}\] \[=-\frac{7}{12}\]. | as desired
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