Answer:
Let the number of boys and girls in a class be \[7x\] and \[5x\] respectively. \[\because \] The number of boys is 8 more than the number of girls. \[\therefore \] \[7x=5x+8\] \[\Rightarrow \] \[7x-5x=8\] | Transposing \[5x\] to LHS \[\Rightarrow \] \[2x=8\] \[\Rightarrow \] \[x=\frac{8}{2}=4\] | Dividing both sides by 2 \[\Rightarrow \] \[7x=7\times 4=28\] and \[5x=5\times 4=20\] \[\therefore \] Total class strength = Number of boys + Number of girls \[=28+20\] = 48 Hence, the total class strength is 48. Check: \[28:20=\frac{28}{20}=\frac{28\div 4}{20\div 4}\] \[=\frac{7}{5}\,=7:5\] |as desired \[28=20+8\] Total class strength \[=28+20=48\].
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