question_answer 1)

                Draw the graphs for the following tables of values, with suitable scales on the axes.                

Number of apples	1	2	3	4	5
Cost (in Rs)	5	10	15	20	25

(b) Distance travelled by a car                

Time (in hours)	6 a.m.	7 a.m.	8 a.m.	9 a.m.
Distances (in km)	40	80	120	160

  (i) How much distance did the car cover during the period 7.30 a.m. to 8 a.m.? (ii) What was the time when the car had covered a distance of 100 km since it's start? (c) Interest on deposits for a year.

Deposit (in Rs)	1000	2000	3000	4000	5000
Simple Interest (in Rs)	80	160	240	320	400

  (i) Does the graph pass through the origin? (ii) Use the graph to find the interest on Rs 2500 for a year. (iii) To get an interest of Rs 280 per year, how much money should be deposited?

Answer:

                (a)     Scale: Horizontal: 2 units = 1 apple Vertical: 1 unit = Rs 5 ? Mark number of apples on horizontal axis. ? Mark cost (in Rs) on vertical axis. ? Plot the points: (1, 5), (2, 10), (3, 15), (4, 20) and (5, 25) ? Join the points. We get a linear graph. (b)   Scale: Horizontal: 2 units = 1 hour Vertical: 2 units = 40 km ? Mark time (in hours) on horizontal axis. ? Mark distances (in km) on vertical axis. ? Plot the points (6 a.m., 40), (7 a.m., 80) (8 a.m., 120) and (9 a.m., 160). ? Join the points. We get a linear graph. (i) Distance covered during 7.30 a.m. to 8 a.m. = 120 km ? 100 km = 20 km (ii) The time when the car had covered a distance of 100 km since its start was 7.30 a.m. (c) Scale: Horizontal: 2 units = Rs 1000 Vertical: 2 units = Rs 80 ? Mark deposit (in Rs) on horizontal axis. ? Mark simple interest (in Rs) on vertical axis. ? Plot the points (1000, 80), (2000, 160), (3000, 240) (4000, 320) and (5000, 400). ? Join the points. We get a linear graph. (i) Yes ! The graph passes through the origin. (ii) Interest on Rs 2500 for a year = Rs 200 (iii) To get an interest of? 280 per year, Rs 3500 should be deposited.