Answer:
\[\frac{4}{10}>\frac{3}{10}\]Tina had length of cloth = 20 m 5 cm = 20 m + 5 cm \[\therefore \] \[0.07=0+0\times \frac{1}{10}+7\times \frac{1}{100}\] \[0.02=0+0\times \frac{1}{10}+2\times \frac{1}{100}\] and length of cloth cut by her = 4 m 50 cm = 4 m + 50 cm \[0.07=\frac{7}{100}\] \[0.02=\frac{2}{100}\] \[\therefore \] \[\frac{7}{100}>\frac{2}{100}\] Length of cloth left with Tina \[\therefore \]Hence, 15.55 m cloth is left with her.
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