question_answer 1)

                A scooter was bought at Rs 42, 000. Its value depreciated at the rate of 8% per annum. Find its value after one year.      

Answer:

                P = Rs 42, 000                 R = 8% per annum \[n=1\]year \[\therefore \]  \[A=P{{\left( 1-\frac{R}{100} \right)}^{n}}\] \[=42,000{{\left( 1-\frac{8}{100} \right)}^{1}}\] \[=42,000\left( 1-\frac{2}{25} \right)\]                 \[=42,000\times \frac{23}{25}=\,\text{Rs}\text{.}\,38,640\]                 Hence, its value after 1 year is Rs 38, 640.