Answer:
(i) After 6 months P = Rs 60,000 R = 12% per annum \[=\frac{1}{2}\times 12%\] per half year = 6% per half year \[n=1\] half year \[\therefore \] \[A=P{{\left( 1+\frac{R}{100} \right)}^{n}}\] \[=60,\,000{{\left( 1+\frac{6}{100} \right)}^{1}}\] \[=60,000\times \frac{106}{100}\,\]= Rs 63, 600 Hence, he would get Rs 63,600 after 6 months. (ii) After 1 year P = Rs 60,000 R = 12% per annum \[=\frac{12}{2}%\] per half year = 6% per half year \[n=1\] year \[=1\times 2\] half years = 2 half years \[\therefore \] \[A=P\,{{\left( 1+\frac{R}{100} \right)}^{n}}\] \[=60,000{{\left( 1+\frac{6}{100} \right)}^{2}}\] \[=60,000{{\left( 1+\frac{3}{50} \right)}^{2}}\] \[=60,000{{\left( \frac{53}{50} \right)}^{2}}\] \[=60,000\times \,\frac{53}{50}\,\times \frac{53}{50}\] = Rs 67,416 Hence, he would get Rs 67,416 after 1 year.
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