Answer:
I = ` 45 R = 9% p.a. Let the sum be ` P. \[\text{I = }\frac{\text{PR}}{\text{100}}\] \[\Rightarrow \] \[45=\frac{P\times 9}{100}\] \[\Rightarrow \] \[P=\frac{45\times 100}{9}=500\] Hence, the sum she borrowed is ` 500.
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