question_answer 30)

Solve the following riddles, you may yourself construct such riddles. Who am I? (i) Go round a square Counting every corner Thrice and no more! Add the count to me To get exactly thirty four!       (ii) For each day of the week make an up count from me If you make no mistake You will get twenty three!       (iii) I am a special number Take away from me a six! A whole cricket team You will still be able to fix! (iv) Tell me who I am  I shall give a pretty clue! You will get me back If you take me out of twenty two!

Answer:

                (i) Let I be denoted by \[x\]. We know that a square has 4 corners and each corner is counted thrice. Total number of comers \[=4\times 3=12\] By given condition, my self + total number of corners     \[x+12=34\] Now,                     \[x=34-12=22\]\[\Rightarrow x=22\] By inspection, we have \[22+12=34\] Thus, I am 22. (ii) Let I be denoted by \[x\]. There are 7 days in a week. By given condition up counting from \[x\] for 7, we get the sum = 23 i.e.          \[x+7=23\] Now,     \[x=23-7=16\]    \[\Rightarrow x=16\] By inspection, we have \[16+7=23\] Thus, I am 16. (iii) Let the special number \[=x\] Then, as per given condition take away 6 from \[x=\] whole cricket team i.e. \[x-6=11\] In cricket team, number of players = 11 Now,     \[x=11+6=17\Rightarrow x=17\] By inspection, we have \[17-6=11\] Thus, the special number is 17. (iv) Let I be denoted by \[x\]. By given condition, take \[x\] out of \[22=x\] \[\Rightarrow \]               \[22-x=x\]           \[\Rightarrow \]\[x+x=22\] \[\Rightarrow \]               \[2x=22\]             \[\Rightarrow \]\[x=11\] By inspection, we have \[2\times 11=22\] Thus, I am 11.