Answer:
The element is carbon. It forms
two oxides: (a) CO and (b)\[C{{O}_{2}}\]. When air is passed over heated carbon
at 1273 K, producer gas is formed.
\[2C+\underset{Air}{\mathop{({{O}_{2}}+{{N}_{2}})}}\,\xrightarrow{2}\underbrace{CO+{{N}_{2}}}_{\Pr
oducer\,gas}\]
CO is a powerful reducing agent.
It reduces ferric oxide into iron.
\[F{{e}_{2}}{{O}_{3}}+CO\xrightarrow{{}}2FeO+C{{O}_{2}}\]
\[FeO+CO\xrightarrow{{}}Fe+C{{O}_{2}}\]
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