question_answer 96)

                Matching the species in column I with the type of hybrid orbitals in column ll.  

Column I	Column II
(i)\[S{{F}_{4}}\]	(a) \[s{{p}^{3}}{{d}^{2}}\]
(ii) \[I{{F}_{5}}\]	(b) \[{{d}^{2}}s{{p}^{3}}\]
(iii)\[NO_{2}^{+}\]	(c) \[s{{p}^{3}}d\]
(iv) \[NH_{4}^{+}\]	(d) \[s{{p}^{3}}\]
	(e) \[sp\]

 

Answer:

    (i?c) , (ii?a), (iii?e) , (iv?d) The type of hybrid orbitals can be evaluated by applying the following formula : \[H=\frac{1}{2}[V+M-C+A]\]                 \[S{{F}_{4}}=\frac{1}{2}[6+4-0+0]=5(s{{p}^{3}}d)\]                 \[I{{F}_{5}}=\frac{1}{2}[7+5-0+0]=6(s{{p}^{3}}{{d}^{2}})\]                 \[NO_{2}^{+}=\frac{1}{2}[5+0-1+0]=2(sp)\]                 \[NH_{4}^{+}=\frac{1}{2}[5+4-1+0]=4(s{{p}^{3}})\]