Answer:
The
Skeletal equation is
\[C{{r}_{2}}O_{7}^{2-}(aq)+SO_{3}^{2-}(aq)\to
C{{r}^{3+}}(aq)+SO_{4}^{2-}(aq)\] 1st step:
Two half equations are
\[C{{r}_{2}}O_{7}^{2-}(aq)\to
2C{{r}^{3+}}and\,SO_{3}^{2-}(aq)\to SO_{4}^{2-}(aq)\]2nd Step: Balancing the element other than hydrogen and oxygen.
\[C{{r}_{2}}O_{7}^{2-}(aq)\to
2C{{r}^{3+}}and\,SO_{3}^{2-}(aq)\to SO_{4}^{2-}(aq)\]3rd Step: Balancing the oxygen by adding water to the oxygen
deficient side.
\[C{{r}_{2}}O_{7}^{2-}\to 2C{{r}^{3+}}+7{{H}_{2}}O\]
and\[SO_{3}^{2-}(aq)+{{H}_{2}}O\to SO_{4}^{2-}(aq)\]
4th Step: Balancing
hydrogen by adding \[{{H}^{+}}\]and change by adding electrons.
\[C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}+6{{e}^{-}}\to
2C{{r}^{3+}}+7{{H}_{2}}O\]
\[[SO_{3}^{2-}(aq)+{{H}_{2}}O\to
SO_{4}^{2-}(aq)2{{H}^{+}}+2{{e}^{-}}]3\]
Adding above two equations such
that the electrons are cancelled out, we get balanced chemical equation.
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