Answer:
\[{{H}_{2}}(g)+B{{r}_{2}}(g)\to
2HBr(g)\]
Heat of reaction \[{{\Delta
}_{r}}H=\Sigma \] Bond energy of reactants
\[-\Sigma \] Bond energy of products
\[=\text{ }\left[ B.E.\left(
H-\text{ }H \right)\text{ }+\text{ }B.E.\left( Br-\text{ }Br \right)
\right]-\text{ }\left[ 2B.E.\left( H-\text{ }Br \right)
\right]\]\[=[435+192]-[2\times 368]\]
\[=-109\text{
}kJ\,mo{{l}^{-1}}\]
You need to login to perform this action.
You will be redirected in
3 sec