Answer:
The present long form of
periodic table has seven periods and the last element of this period is the
element with atomic number 118.
Thus, the element with atomic
number 119 is the first member of 8th period and a member of alkali group with outer
electronic configuration, \[8{{s}^{1}}\]. It belongs to first group and therefore,
its valency is one. The formula of its oxide is\[{{M}_{2}}O\].
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