Answer:
(d) Tetravalency of tin
is mere stable than divalency. Thus,\[SnC{{l}_{2}}\] acts as a reducing agent.
\[SnC{{l}_{2}}+2HgC{{l}_{2}}\xrightarrow{{}}SnC{{l}_{4}}+H{{g}_{2}}C{{l}_{2}}\]
\[SnC{{l}_{2}}+H{{g}_{2}}C{{l}_{2}}\xrightarrow{{}}SnC{{l}_{4}}+2Hg\]
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