question_answer 47)

  What will be the molarity of a solution, which contains 5.85 g of \[NaCl(s)\] per 500 mL? (a) \[4mol{{L}^{-1}}\]                     (b) \[20\,mol\,{{L}^{-1}}\] (c) 0                                       (d) \[2\,mol\,{{L}^{-1}}\]

Answer:

  (c) Molarity, \[M=\frac{{{w}_{B}}\times 1000}{{{m}_{B}}\times V}=\frac{5.85\times 1000}{58.5\times 500}=0.2mol\,{{L}^{-1}}\]