Answer:
Boric acid
itself does not release hydrogen ions. When it reacts with water, it receives \[O{{H}^{-}}\]
ions from water molecules to complete its octet and releases \[{{H}^{+}}\]
ions.
\[\underset{Orthoboric\,acid}{\mathop{B{{(OH)}_{3}}}}\,+2{{H}_{2}}O\to
{{[B{{(OH)}_{4}}]}^{-}}+{{H}_{3}}{{O}^{-}}\]
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