Answer:
(i) Number of atoms = \[\frac{W}{{{A}_{w}}}\times
6.023\times {{10}^{23}}\]
\[=\frac{1}{197}\times
6.023\times {{10}^{23}}\]
\[=3.06\times
{{10}^{21}}atoms\]
(ii) Number
of atoms = \[\frac{1}{23}\times 6.023\times {{10}^{23}}\]
\[=2.62\times
{{10}^{22}}atoms\]
(iii) Number
of atoms = \[\frac{1}{39}\times 6.023\times {{10}^{23}}\]
(iv) Number
of molecules = \[\frac{W}{{{M}_{w}}}\times 6.023\times {{10}^{23}}\]
\[=\frac{1}{71}\times
6.023\times {{10}^{23}}\]
Number of
atoms = \[2\times \frac{1}{71}\times 6.023\times {{10}^{23}}\]
\[=1.67\times
{{10}^{22}}atoms\] atoms
\[\therefore \] 1 g Na has maximum number of atoms.
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