Answer:
Amount of heat absorbed by the
system
\[=+286kJ\,mo{{l}^{-1}}\]
\[\Delta S=\frac{q}{T}=\frac{286\times 1000}{298}\]
\[=959.73J{{K}^{-}}mo{{l}^{-1}}\]
You need to login to perform this action.
You will be redirected in
3 sec