Answer:
Given, in last 30 days, temperature drop = 15 degree \[\therefore \] In 1 day, temperature drop \[=\frac{15}{30}\]degree \[=\frac{15\div 15}{30\div 15}=\frac{1}{2}\]degree [\[\because \]HCF of 15 and 30 = 15] \[\therefore \] In next 10 days, temperature drop \[=\frac{1}{2}\times 10\] degree = 5 degree Hence, temperature dropped 5 degree in the next 10 days.
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