question_answer 25)

The energy of an electron in the ground state of the hydrogen atom is\[-2.18\times {{10}^{-18}}J\]. Calculate the ionisation energy (enthalpy) of atomic hydrogen in J \[mo{{l}^{-1}}.\]

Answer:

\[IE={{E}_{\infty }}-{{E}_{n}}\] \[=0-(-2.18\times {{10}^{-18}})=2.18\times {{10}^{-18}}J\] Ionisation enthalpy per mole \[=2.18\times {{10}^{-18}}\times 6.023\times {{10}^{23}}\] \[=1.313\times {{10}^{6}}J\]