Answer:
(a) ln\[AgBr,A{{g}^{+}}\]is reduced to Ag.
\[AgBr\]is oxidising agent.
In \[{{C}_{6}}{{H}_{6}}{{O}_{2}},\]carbon is oxidised
\[{{C}_{6}}{{H}_{6}}{{O}_{2}}\]is reducing agent
(b) \[HCHO\]is oxidised to \[HCO{{O}^{-}}\]
\[HCHO\]is reducing agent.
\[{{[Ag{{(N{{H}_{3}})}_{2}}]}^{+}}\]is reduced to Ag.
\[{{[Ag{{(N{{H}_{3}})}_{2}}]}^{+}}\]is oxidising agent.
(c) \[HCHO\]is oxidised to \[HCO{{O}^{-}}\].
\[HCHO\]is reducing agent.
\[C{{u}^{2+}}\]is reduced to \[C{{u}^{+}}\]\[(C{{u}_{2}}O).\]
\[C{{u}^{2+}}\]is oxidising agent.
(d) \[{{N}_{2}}{{H}_{4}}\]is oxidised to \[{{N}_{2}}\](loss
of hydrogen)
\[{{N}_{2}}{{H}_{4}}\]is reducing agent.
\[{{H}_{2}}{{O}_{2}}\]is reduced to \[{{H}_{2}}O\]
\[{{H}_{2}}{{O}_{2}}\]is oxidising agent.
(e) \[\overset{0}{\mathop{Pb}}\,(s)\]is oxidised to \[\overset{2+}{\mathop{Pb}}\,SO_{4}^{2-}\].
\[Pb\]is reducing agent.
\[\overset{+4-4}{\mathop{Pb{{O}_{2}}}}\,\]is reduced to \[\overset{+4-4}{\mathop{PbSO_{4}^{2-}}}\,\]
\[Pb{{O}_{2}}\]is oxidising agent.
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