Answer:
Required equation:
\[C(s)+2{{H}_{2}}(g)\to
C{{H}_{4}}(g)\]
(i) \[C{{H}_{4}}(g)+2{{O}_{2}}(g)\to
C{{O}_{2}}(g)+2{{H}_{2}}O(l)\]
\[=\Delta
{{H}^{{}^\circ }}=-890.3KJmo{{l}^{-1}}\]
(ii) \[C(s)+{{O}_{2}}(g)\to
C{{O}_{2}}(g)\Delta {{H}^{{}^\circ }}=-393.5kJ\,mo{{l}^{-1}}\]
(iii) \[2{{H}_{2}}(g)+{{O}_{2}}(g)\to
2{{H}_{2}}O(l)\Delta {{H}^{{}^\circ }}=-2\times 285.8kJmo{{l}^{-1}}\]
Adding (ii)
and (iii), subtracting (i) we get
\[C(s)+2{{H}_{2}}(g)\to
C{{H}_{4}}(g)\]
\[\Delta {{H}^{{}^\circ
}}=(-393.5)+(-2\times 285.8)-(-890.3)\]
\[=-74.8kJ\,mo{{l}^{-1}}\]
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