Answer:
The
molecular formula of the 5th member of alkyne series is \[{{C}_{6}}{{H}_{10}}\].
The possible isomers are:
(i) \[H\overset{1}{\mathop{C}}\,\equiv
\overset{2}{\mathop{C}}\,-\underset{Hex-1-yne}{\mathop{\overset{3}{\mathop{C{{H}_{2}}}}\,\overset{4}{\mathop{C{{H}_{2}}}}\,\overset{5}{\mathop{C{{H}_{2}}}}\,}}\,{{\overset{6}{\mathop{CH}}\,}_{3}}\]
(ii) \[C{{H}_{3}}-C\underset{Hex-2-yne}{\mathop{\equiv
C-C{{H}_{2}}}}\,C{{H}_{2}}C{{H}_{3}}\]
(iii) \[C{{H}_{3}}C{{H}_{2}}\underset{Hex-3-yne}{\mathop{C\equiv
CC{{H}_{2}}}}\,C{{H}_{3}}\]
(iv) \[HC\equiv
C-\underset{\underset{\underset{3-Methylpent1-yne}{\mathop{\text{C}{{\text{H}}_{\text{3}}}}}\,}{\mathop{\text{
}\!\!|\!\!\text{ }}}\,}{\mathop{CHC{{H}_{2}}}}\,C{{H}_{3}}\]
(v) \[HC\equiv C-\underset{\underset{\underset{4-Methylpent-1-yne}{\mathop{\text{C}{{\text{H}}_{\text{3}}}}}\,}{\mathop{|}}\,}{\mathop{C{{H}_{2}}CHC{{H}_{3}}}}\,\]
(vi) \[C{{H}_{3}}C\equiv
C-\underset{\underset{\underset{4-Methylpent-2-yne}{\mathop{\text{C}{{\text{H}}_{\text{3}}}}}\,}{\mathop{|}}\,}{\mathop{CHC{{H}_{3}}}}\,\]
(vii) \[\underset{3,3-Dimethylbut\,-1-yne}{\mathop{HC\equiv
C-\underset{\underset{\text{C}{{\text{H}}_{\text{3}}}}{\mathop{|}}\,}{\overset{\overset{\text{C}{{\text{H}}_{\text{3}}}}{\mathop{|}}\,}{\mathop{C}}}\,-C{{H}_{3}}}}\,\]
Chain and position isomerism is
shown by different pairs.
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