Answer:
\[N{{a}_{2}}O\]reacts with water and
forms a strong base, i.e. sodium hydroxide.
\[N{{a}_{2}}O+{{H}_{2}}O\to
2NaOH\]
\[\text{C}{{\text{l}}_{\text{2}}}{{\text{O}}_{\text{7}}}\]reacts
with water and forms a strong acid, perchloric acid.
\[C{{l}_{2}}{{O}_{7}}+{{H}_{2}}O\to
2HCl{{O}_{4}}\]
Both the
products can be tested qualitatively with litmus paper.
\[NaOH\] + Red
litmus paper Blue colour
\[HCl{{O}_{4}}\] + Blue litmus paper Red colour
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