question_answer 82)

In a game, a man wins a rupee for a six and losses a rupee for any other number when a fair die is thrown. The man decided to throw a die thrice but to quit as when he gets a six. Find the exacted value of the amount he wins /loses. 

Answer:

E be the event of getting 6 and  be the even of not getting 6. Let X be the amount the man gained/lost.                                                                             Probability distribution                     Expected value of X = E(x)