question_answer 38)

An insurance company insured 2000 scooter drivers, 4000 car drivers and 6000 truck drivers. The probabilities of the accidents are 0.01, 0.03 and 0.15 respectively. One of the insured persons meets with an accident. What is the probability that he is a scooter driver ? 

Answer:

Let E1, E2 and E3 are the events of selection of a scooter driver, car driver and truck driver respectively.       Let A = event that the insured person meets with an accident.                         P(A/E1) = 0.01, P(A/E2) =  0.03       P(A/E3) = 0.15       Required probability = P(E1 /A)