Answer:
We
have P(A) = 0.3, P(B) = 0.6 and A and B are independent events. Therefore, are also
independent events.
(i) P(A and B)
= P(A B)
(AB) = P(A) ×
P(B)
0.3 × 0.6 = 0.18
(ii) P(A and not B)
= P (A) = P(A) ×
= 0.3 × (1 ?
0.6) = 0.3 × 0.4 = 0.12
(iii) P(A or B) = P(A
B) = 1 ?
P
= 1?
P
= 1
? 0.28 = 0.72
(iv) P (neither A nor
B) = 1 ? P(A or B)
= 1 ?0.72 =
0.28 {Using (iii)}
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