Answer:
Total
bulbs = 30
Number
of Defective bulbs = 6
Number
of Non defective bulbs = 30 ? 6 = 24.
probability
of getting a defective bulb,
Let
X is the random variable of ?Number of defective bulbs?
P(X
= 1)
P(X
=2)
P(X
= 3)
Probability
distribution is
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