: 2x + y = 3 L2 : x + 2y = 6
Z is minimum at B(0, 3) and E(6, 0)
the region is unbounded.
may or may not
be the minimum value of Z.
this draw graph of inequality.
+ 2y < 6
: x + 2y = 6
open half plane has no common point with the feasible region.
minimum value of Z is 6
optimal solution is x = 0, y = 3 or x = 6, y = 0
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