Answer:
Let
number of cakes of first kind = x
and
the number of cakes of second kind = y
The
contents of cake are given below
Therefore
the above L.P.P. is given as maximize,
Z
= x + y, subject to the constraints.
200
x + 100 y
and
25x + 50 y
i..e. 2x
+ y
and
x + 2y
L1:
2x + y = 50 L2 : x + 2y = 40
Here
Z is maximum at E(20, 10)
Number of cake
of first kind x =20
Number
of cakes of second kind, y = 10
Maximum number
of cakes = 20 +10 = 30.
Cake
Flour
Fat
First kind
200
25
Second Kind
100
50
Quantity
available
5 kg
1 kg
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