Answer:
Operate we get
Take 2(a + b +
c) as common
Operate
Expand along C1
.
= 2(a + b
+ c) . [(b ? c) (c ? b) ? (b ? a) (c ? a)]
= 2(a + b
+ c) . [? (b ? c)2 ? (bc ? ab ? ac + a2)]
= 2 (a + b
+ c) [?b2 ? c2 + 2bc ? bc + ab + ac ? a2]
= ?2 (a +
b + c) (a2 + b2 + c2 ? ab ? bc ? ca)
= ? (a + b
+ c) (2a2 + 2b2 + 2c2 ? 2ab ? 2bc ? 2ca)
= ? (a + b + c)
(a2 + b2 ? 2ab + b2 + c2 ? 2bc + c2
+ a2
? 2ca)
Given
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