Answer:
The given system of
equations can be expressed as AX = B, where
and
= 1 (1 + 3) + 1
(2 + 3) + 1 (2 ? 1)
= 4 + 5 +
1 = 10 0
Therefore A is
non-singular matrix so A?1 exists and given system has unique
solution.
A11 =
4; A12 = ?5; A13 = 1
A21 =
2; A22 = 0; A23 = ?2
A31 =
2; A32 = 5; A33 = 3
adj
Now AX = B
On equating, we
get x =2, y = ?1, z = 1.
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