Answer:
Let 
= 6 + 8 =
14 
0
is
non-singular matrix, so A?1 exists
A11 =
(?1)1+1 . 3 = 3;
A12 =
(?1)1+2 . 4 = ?4;
A21 =
(?1)2+1 . (?2) = 2;
A22 =
(?1)2+2 . 2 = 2;
Now 
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