Answer:
Let
So 2X + 3Y + 10Z
= 4
4X ? 6Y + 5Z =1
6X + 9Y ? 20Z =
2
The above system
can be expressed as
AX = B, when A
= 2(120 ? 45) ?
3(?80?30) + 10 (36 + 36)
= 150 + 330 +
720 = 1200 0
Therefore A is
non-singular matrix so A?1 exists and given system has unique
solution.
A11 =
75; A12 = 110; A13 = 72
A21 =
150; A22 = ?100; A23 = 0
A31 =
75; A32 = 30; A33 = ?24
Adj
Now XY = B
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