Answer:
let
Operate
Take a + b + c
as common from C1
Operate we get
Expand along C1
= (a + b
+ c) [(a + 2b) (a + 2c) ? (a ? c) (a ? b)]
= (a + b + c)
[(a2 + 2ac + 2ab + 2ac) ? (a2 ? ac ?ab + bc)]
= (a + b + c) [a2
+ 2ac + 2ab + 4bc ? a2 + ab + ac ? bc]
= (a + b + c)
[3ab + 3bc + 3ca]
= 3 (a + b + c)
(ab + bc + ca)
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