question_answer 1)

Show that         = (x ? y) (y ? z) (z ? x) (xy + yz + zx)  

Answer:

Let       Multiplying R1, R2 and R3 by x, y and z respectively, we get             Taking xyz as common from C3             Operate  we get             Taking (y ? x) and (z ? x) as common from R2 and R3, we get             Expand along C3, we get             Operate             Taking y ? z as common from R1             = (y ? x) (z ? x) (y ? z)             [z2 + zx + x2 ? (z + x) (x + y + z)]       = (y ? x) (z ? x) (z2 + zx + x2 ? zx ? zy ? z2 ? x2 ? xy ? zx)             = (y ? x) (z ? x) (y ? z) (?xy ? yz ? zx)             = (x ? y) (y ? z) (z ? x) (xy + yz + zx)