Answer:
Let
Operate we get
Taking (b ? a)
and (c ? a) as common from C2 and C3 respectively.
Expand along R1,
we get
= (b ? a) (c ?
a)
[c2 +
ac + a2 ? b2 ? ab ? a2]
= (b ? a) (c ?
a) (c2 ? b2 + ac ? ac)
= (b ? a) (c ?
a) ((c ? b) (c + b)
+
a (c ? b))
= (b ? a) (c ?
a) (c + b + a)
= (a ? b) (b ?
c) (c ? b) (a + b + c)
You need to login to perform this action.
You will be redirected in
3 sec