Answer:
Let
x cm be the side of the square to be cut from from corner at the given square
piece of tin of side 18cm.
Therefore
the box.
l
= 18 ? 2x cm. b = 18 ? 2x cm.
and
h = x cm
Volume of
the box
V
= lbh = (18 ? 2x)2x
=
(324 + 4x2 ? 72x) x
but
x = 9 which is
impossible
x = 3
Now
=
V is maximum when x = 3
Hence
volume of the box will be maximum when the side of the square to be cut from
each corner = 3 cm.
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