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12th Class Mathematics Applications of Derivatives

  • question_answer 59)
    Find the approximate value of f(2.01) where f(x) = 4x2 + 5x + 2. 

    Answer:

    2.01 = 2 + 0.01       Let x = 2, Taking y = f(x)                                       .?. (1)                                            ?? (2)       Using approximation       (3)                         = 28 + (8x + 5) (0.01)       = 28 + (8 × 2 + 5) (0.01)       = 28 + 0.21 = 28.21.        


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